Math, asked by ruksharnaaz234, 5 hours ago

find p(0), p(1) and p(2) for P(x) = (x-1) (x+1)​

Answers

Answered by RealSweetie
2

p(x)=(x-1)(x+1)

p(0)=(0-1)(0+1)= -1× 1= -1

p(1)=(1-1)(1+1)=0×2=0

p(2)=(2-1)(2+1)=1×3=3

Answered by gouravgupta65
1

Answer:

P(0) = -1

P(0) = -1 P(1) = 0

P(0) = -1 P(1) = 0P(2) = 3

Step-by-step explanation:

P(x) = (x-1) (x+1)

P(x) = x² - 1

P(0) = -1

P(1) = 0

P(2) = 3

Hope this help you

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