Question

find p(0),p(1) then p(y)=2+y+2y^2-y^3​

Answer 1

Answer:

I hope it helps...

Step-by-step explanation:

p(0)=2+0+2×0^2-0^3

=2+0+0+0

=2

p(1)=2+1+2×1^2-1^3

=2+1+2-1

=4

Answer 2

Answer:

1567

Step-by-step explanation:

2×79+34-67÷45+89π56