Question

find p(1/3) for p(t) = t²-t+2

Answer 1

(1/3)^2-(1/3)+2
=(1/9)-(1/3)+2
=(1-3+18)/9
=16/9

Answer 2

Given,

A function of t, such that, p(t)=$t^{2} -t+2$

To Find,

The value of p($\frac{1}{3}$).

Solution,

Here p(t) is a function of t .

That means p(t) value is dependent upon the value of t.

p(t) is denoted by an equation, $t^{2} -t+2$ .

So when t=$\frac{1}{3}$ , p($\frac{1}{3}$) = $(\frac{1}{3} )^{2} -\frac{1}{3} +2$

⇒p($\frac{1}{3}$)=$\frac{1}{9}$-$\frac{1}{3}$+2.

⇒p($\frac{1}{3}$)=$\frac{1-3+18}{9}$..

⇒p($\frac{1}{3}$)=$\frac{16}{9}$.

Hence, the value of p($\frac{1}{3}$) is $\frac{16}{9}$.