find p(-2) if p(x)=3-x-2x^2-x^3 polynomial
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Answer:
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Answer: P(2)=2+(2)+2(2)^{2}-(2)^{3} P(2)=4+8-8 P(2)=4
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Answered by
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p(x) = 3x³ - 2x² - x + 4
p(- 1) = 3(-1)³ - 2(-1)² - (-1) + 4
p(- 1) = 3 × (-1) - 2 × 1 + 1 + 4
p(- 1) = - 3 - 2 + 5
p(- 1) = - 5 + 5 = 0
p(- 1) = 0
So, as per Factor Theorem
-1 is zero if p(x)
hope it helps you :)
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