Question

Find p if mean of follwing distribution is 20 x : 15,17,19,20+p ,23 and f : 2,3,4,5p,6

Answer 1

here is your answer,

(x) (f) (fx)
15 2 30
17 3 51
19 4 76
(20+p) 5p (100p+5p^2)
23 6 138

so the sum of (fx) is ------
=(30+51+76+100+5p^2+138)
=(395+5p^2)
the sum of (f) is =(15+5p)
the mean of the following distribution is 20
so, According to the question ------
$\frac{(395 + {5p}^{2} )}{(15 + 5p)} = 20 \\ or \: \: (395 + 5 {p}^{2} ) = 300 + 100p \\ or \: \: 5 {p}^{2} - 100p + 95 = 0 \\ or \: \: 5( {p}^{2} - 20p + 19) = 0 \\ or \: \: {p}^{2} - 19p - p + 19 = 0 \\ or \: \: p(p - 19) - 1(p - 19) = 0 \\ or \: \: (p - 19)(p - 1) = 0$
so either p=19 or 1【Answer】
Hope it helps, pls mark it brainliest.

Answer 2

Hi there!

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What is Mean?

The average of a given set of numbers is called the Arithmetic mean, or simply the mean, of the given numbers.

Mean = $\frac{Sum \: of \: observations }{Number \: of \: observations }$

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For your solution to the given question refer to the attachment.

Thanks for the question!

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