Find perimeter of rectangle l=40 D=41
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Answered by
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Heya.
Here is your answer....
Perimeter of rectangle = 2 (l+b)
= 2 (40+41)
= 2 ( 81)
= 162.
Therefore the perimeter of rectangle is 162cm.
Answered by
0
Length = 40 unit
Diagonal = 41 unit
Breadth= Have to find.
We know, all sides of rectangle are perpendicular to each other,
By Pythagoras Theorem,
( length )^2 + ( breadth )^2 = ( diagonal )^2
( 40 )^2 + ( breadth )^2 = ( 41 )^2
( breadth )^2 = ( 41 )^2 - ( 40 )^2
( breadth )^2 = 81
breadth = 9 unit
Then,
Perimeter of rectangle = 2( 49 )
Perimeter of rectangle = 98 unit
Diagonal = 41 unit
Breadth= Have to find.
We know, all sides of rectangle are perpendicular to each other,
By Pythagoras Theorem,
( length )^2 + ( breadth )^2 = ( diagonal )^2
( 40 )^2 + ( breadth )^2 = ( 41 )^2
( breadth )^2 = ( 41 )^2 - ( 40 )^2
( breadth )^2 = 81
breadth = 9 unit
Then,
Perimeter of rectangle = 2( 49 )
Perimeter of rectangle = 98 unit
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