Math, asked by niyajuddin1902, 9 months ago

Find perimeter of rectangle whose length is 8 cm and length of diagonals is 10 cm.

Answers

Answered by dalelamanya

6

Answer:

by Pythagoras we get (AC)^2=(AB)^2+(CB)^2

therefore ,BC =6

perimeter =2(length+breath)

=2(8+6)

=2*14

28

Hope it helps

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