Question

find position and nature of image of an object 3 cm high placed at a distance 6 cm from a concave mirror of focal length 12 cm​

Answer 1

Given: f= -12cm, u= -6cm, O= 3cm

$\frac{1}{f} = \frac{1}{v} - \frac{1}{u}$

$- \frac{1}{12} = \frac{1}{v} + \frac{1}{6}$

$\frac{1}{v} = \frac{ - 1 - 3}{12}$

$\frac{1}{v} = - \frac{ - 1}{3}$

$v = - 3cm$