Question

Find pressure excerted by 6.4g of oxygen in 3l flask at 27°c.
Please answer urgently. ​

Answer 1

Answer:

Explanation:

Formula to solve the problem PV=nRT

Wt of oxygen=6.4gm

Gma of oxygen=32gm

Volume V=3lit given

Gaseous constant R=0.0821lit atmmole-1k-1

TemperatureT=27℃=300K

Mole no of KE=6.4/32=0.2

P=nRT/V

P=0.2×0.0821×300/3=1.642atm