Question

Find probability of 53 Sundays in a leap year !!

Answer 1

The solution to your given question is:--
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☆

Number of days in a leap year =366 days =52 weeks and 2 days

Now 52 weeks contain 52 Sundays and the remaining two days will be one of the
following seven possibilities:---

(Sun,Mon) (Mon,Tue),(Tue,Wed), (Wed,Thu),(Thu,Fri),(Fri,Sat) and (Sat,Sun)

The probability of 53 Sundays in a leap year is the same as the probability of getting
a Sunday in the above seven possibilities.

Required probability is 2/7. ☆

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LOL

Answer 2

$Heya \: @EshanSingh !!! \\ This \: is \: your \: answer. \\ To \: find :- \\ Probability \: of \: 53 \: Sundays \: in \: a \: \\ Leap \: Year. \\ \\ Now, \\ Solution :- \\ Days \: in \: a \: Leap \: Year = 366. \\ Weaks \: in \: the \: leap \: year = 366/7 \\ => Quotient= 52.... Remainder = 2. \\ Hence, \: there \: are \: 52 \: weeks \: and \\ two \: days \: in \: the \: leap \: year. \\ \\ As \: there \: are \: 52 \: weeks, \\ then \: there \: will \: be \: 52 \: Sundays \\ for \: sure. \\ \\ Now, \: about \: the \: two \: days :- \\ \\ They \: can \: be \: of \: following \: combination.$
$Monday, \: Tuesday \\ Tuesday, \: Wednesday \\ Wednesday, \: Thursday \\ Thursday, \: Friday \\ Friday, \: Saturday \\ Saturday, \: Sunday \\ Sunday, \: Monday$
$So, \: there \: are \: 7 \: probabilities. \: \\ Out \: of \: which \: probablity \: of getting \: Sunday \: is \: 2. \\ \\ Hence, \: the \: probability \: of \: 53 \: Sundays \\ \: in \: a \: Leap \: Year \: is \frac{2}{7} . \\ \\ \\ Hope \: It \: Helps.........$