FIND PROBABILITY THAT MEAN OF A SAMPLE OF SIZE 25 TAKEN FROM NORMAL POPULATION WITH MEAN 5000 AND STANDARD DEVIATION 1300 IS GREATER THAN 5400.
Answers
Answered by
3
well it is normal distribution question
mean=5000
S.D=1300
n=25
X is random variable
and X=5400
Z=X-mean/S.D=(5400-5000)/1300=4/13=0.31
so for Probablilty
P(X>5400)=0.5-P(0.31>Z>0)=0.3783
mean=5000
S.D=1300
n=25
X is random variable
and X=5400
Z=X-mean/S.D=(5400-5000)/1300=4/13=0.31
so for Probablilty
P(X>5400)=0.5-P(0.31>Z>0)=0.3783
Answered by
2
probability for given que is 0.3783
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