Question

Find product 1+3 root 2 and 1-3 root 2

Answer 1

$Product \:of \: ( 1 + 3\sqrt{2} )\: and$

$( 1 - 3\sqrt{2} )$

$= ( 1 + 3\sqrt{2} )( 1 - 3\sqrt{2} )$

$= 1^{2} - (3\sqrt{2})^{2}$

/* By algebraic identity */

$\boxed{\pink{ (x+y)(x-y) = x^{2} - y^{2} }}$

$= 1 - 18$

$= -17$

Therefore.,

$\red{Product \:of \: ( 1 + 3\sqrt{2} )\: and }$

$\red{( 1 - 3\sqrt{2} )} \green { = -17}$

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Answer 2

${\tt{\purple{\underline{\underline{\huge{Answer:}}}}}}$

$\large{ Product \:of \: ( 1 + 3\sqrt{2} )\: and\: ( 1 - 3\sqrt{2} ) }$

$\sf\implies ( 1 + 3\sqrt{2} )( 1 - 3\sqrt{2} )$

$\sf\implies 1^{2} - (3\sqrt{2})^{2}$

$\boxed{ (x+y)(x-y) = x^{2} - y^{2} }$

$\sf\implies 1 - 18$

$\sf\implies -17$

$Product \:of \: ( 1 + 3\sqrt{2} )and \:( 1 - 3\sqrt{2} )=-17$

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