Find q no.15 plzzzz if possible then solve it.....also q no.14 and 13 number....
Agar ho hi karna
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15. 'n' is odd
(x+1) is a factor== x=-1...so the eqn. reads (-1)^n + 1 =0, for n=odd
14. A
X= root(7+4rt3)... 1/X = 1/root(7+4rt3) = root(7-4rt3)/rt1 = root(7-4rt3) [by rationalizing the denominator]
Now find (X + 1/X) ^2 = X^2 + 1/X^2 +2 = 7+4rt3 + 7 - 4rt3 +2 = 16
Therefore, X+1/X =rt16 =4
13.B
Substitute the values (2k-1) for 'x' and and 'k' for 'y'
20k-10-9k=12....11k=22....k=2
(x+1) is a factor== x=-1...so the eqn. reads (-1)^n + 1 =0, for n=odd
14. A
X= root(7+4rt3)... 1/X = 1/root(7+4rt3) = root(7-4rt3)/rt1 = root(7-4rt3) [by rationalizing the denominator]
Now find (X + 1/X) ^2 = X^2 + 1/X^2 +2 = 7+4rt3 + 7 - 4rt3 +2 = 16
Therefore, X+1/X =rt16 =4
13.B
Substitute the values (2k-1) for 'x' and and 'k' for 'y'
20k-10-9k=12....11k=22....k=2
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