find roots of the quadratic equation 6x^2_x_2=0
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Answer:x=(2/3),(-1/2)
Step-by-step explanation:
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6x^2-x-2 = 0
6x^2-4x-3x-2 = 0
2x(3x-2)-1(3x-2) = 0
(3x-2)(2x-1) = 0
3x-2 = 0 & 2x-1 = 0
3x = 2 2x = 1
x = 2/3 x = 1/2
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