Chemistry, asked by fiitjeeharsh, 8 months ago

Find S for the conversion of 10.0 g of supercooled water at 10oC and 1.00 atm to ice at – 10oC

and 1.00 atm. average Cp values for ice and supercooled water in the range 0oC to – 10oC are

0.50 and 1.01 cal/(g, oC), respectively.​

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Answered by Sakshi3090
0

Answer:

Step 1 of 5

The conversion of super cooled water to ice at  is as follows:

The process is takes place under 1 atm pressure.

Calculate the entropy for the three processes and add them to get the final entropy.

The mass of super cooled water is 10.0 g.

The heat capacity value of water at  is  and at  is  .

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