find sinx/2 cos x/2 tanx/2 if cosx=-⅓ X is in iii quadrant
Answers
Answered by
4
2sinx cosx=sin2x
sin2x=2tan(x/2)/1+tan^2(x/2)
1/2(sinx)tan(x/2)
1/2(2tan^2(x/2))/1+tan^(x/2)
sinx=-root of(8)/3
2sin(x/2)cos(x/2)=-root8/3
dividing with cos^2(x/2)
tan(x/2)=-3root8 /2
answeris
9(8)/4/1+9(8)/4
72/76
18/19
sin2x=2tan(x/2)/1+tan^2(x/2)
1/2(sinx)tan(x/2)
1/2(2tan^2(x/2))/1+tan^(x/2)
sinx=-root of(8)/3
2sin(x/2)cos(x/2)=-root8/3
dividing with cos^2(x/2)
tan(x/2)=-3root8 /2
answeris
9(8)/4/1+9(8)/4
72/76
18/19
royalbramhan1:
yeah
correct that
cos(x/2)is not -1/3
i am sorry
cos(x/2)is 1/root (3) if substitiue it we will get a correct answer
wait i will tell the answer
is 2/3 is right answer
sorry is not necessary
your answer is again wrong
it's again wrong
Similar questions