Math, asked by tsinghtanuja, 3 months ago

find
square root of 47 by coloum method​

Answers

Answered by kjashanpreet2004
0

Step-by-step explanation:

Here, a=3 and b=7

Step 1: Make 3 columns and write the values of a ^2 ,2×a×b and b ^2 in these columns.

Column I Column II Column III

a ^2 2×a×b b ^2

9 42 49

Step 2: Underline the unit digit of b ^2

(in Column III ) and add its tens digit, if any, with 2×a×b ( in column II )

Column I Column II Column III

a ^2 2×a×b b ^2

9+4 42+4 49

13 46

Step 3: Underline the unit digit in Column II and add the number formed by the tens and other digits if any, with a^2 in ColumnI.Underlinenumber in column I.

Column I Column II Column III

a^2 2×a×b b

9+4 42+4 49

13 46

Step 4: Write the underline digits at the bottom of each column to obtain the square of the given number.

In this case, we have:

37^2 =1369

Using multiplication :

37×37=1369

This matches with the result obtained the column method.

Hope you will great help from this example

Its step by step explanation

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