find
square root of 47 by coloum method
Answers
Step-by-step explanation:
Here, a=3 and b=7
Step 1: Make 3 columns and write the values of a ^2 ,2×a×b and b ^2 in these columns.
Column I Column II Column III
a ^2 2×a×b b ^2
9 42 49
Step 2: Underline the unit digit of b ^2
(in Column III ) and add its tens digit, if any, with 2×a×b ( in column II )
Column I Column II Column III
a ^2 2×a×b b ^2
9+4 42+4 49
13 46
Step 3: Underline the unit digit in Column II and add the number formed by the tens and other digits if any, with a^2 in ColumnI.Underlinenumber in column I.
Column I Column II Column III
a^2 2×a×b b
9+4 42+4 49
13 46
Step 4: Write the underline digits at the bottom of each column to obtain the square of the given number.
In this case, we have:
37^2 =1369
Using multiplication :
37×37=1369
This matches with the result obtained the column method.
Hope you will great help from this example
Its step by step explanation