Find sum of zeros of polynomial ax2+2x+3a if sum of zero is equal to their product
Answers
Answered by
21
hello users .......
we have given that:-
for a quadratic equation :: ax² + 2x + 3a = 0
the sum and the product of roots are equal ;
solution:-
here;
we know that :
For a quadratic equation : ax² + bx + c = 0
sum of roots = - b / a ;
and
product of roots = c / a
here,
sum of roots = - b / a = - 2 / a
and
product of roots = c / a = 3a / a = 3
According to question ;
sum of roots = product of roots
=> -2 / a = 3
=> a = -2 / 3
now; put the value of a in the givn equation .
we get ,
(-2 / 3) x² + 2x + ( -2 / 3) = 0
=>- 1/3 (2 x² - 6x +2 ) = 0 ...taking (-1/3) common ;
hence;
the required quadratic equation is : 2x² - 6x + 2 = 0 answer
✰✰ hope it helps ✰✰
we have given that:-
for a quadratic equation :: ax² + 2x + 3a = 0
the sum and the product of roots are equal ;
solution:-
here;
we know that :
For a quadratic equation : ax² + bx + c = 0
sum of roots = - b / a ;
and
product of roots = c / a
here,
sum of roots = - b / a = - 2 / a
and
product of roots = c / a = 3a / a = 3
According to question ;
sum of roots = product of roots
=> -2 / a = 3
=> a = -2 / 3
now; put the value of a in the givn equation .
we get ,
(-2 / 3) x² + 2x + ( -2 / 3) = 0
=>- 1/3 (2 x² - 6x +2 ) = 0 ...taking (-1/3) common ;
hence;
the required quadratic equation is : 2x² - 6x + 2 = 0 answer
✰✰ hope it helps ✰✰
Answered by
7
Answer:
Step-by-step explanation:
From the equation we get,
a=a, b=2, c=3a
Let Roots of the equation be m and n.
so, m+n =-b/a. mn =c/a,
-2/a ÷3a/a
-2/3a
a=-2/3
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