Question

find ten rational number between -3 upon 11 and and 8 upon 11

Answer 1

Hope it is correct!!!

Answer 2

Answer:

The rational numbers are

$\frac{-2}{11}, \frac{-1}{11}, \frac{0}{11}, \frac{1}{11}, \frac{2}{11}, \frac{3}{11}, \frac{4}{11}, \frac{5}{11}, \frac{6}{11}, \frac{7}{11}$

Step-by-step explanation:

$\text{Given two numbers }\frac{-3}{11}\text{ and }\frac{8}{11}$

we have to find ten rational number between above two numbers

The two numbers are

$\frac{-3}{11}\text{ and }\frac{8}{11}$

As the denominator are equal therefore we just have to take the 10 numbers between the numerator.

The numerators are -3 and 8

The numbers between these two are

-2, -1, 0, 1, 2, 3, 4, 5, 6, 7

$\text{Hence, the rational number between }\frac{-3}{11}\text{ and }\frac{8}{11}\text{ are}$

$\frac{-2}{11}, \frac{-1}{11}, \frac{0}{11}, \frac{1}{11}, \frac{2}{11}, \frac{3}{11}, \frac{4}{11}, \frac{5}{11}, \frac{6}{11}, \frac{7}{11}$

which are required rational numbers.