Math, asked by archit47, 1 year ago

find
1 \div  \sqrt{2 }  + \pi
if root 2=1.141&π=3.141


archit47: please answer

Answers

Answered by mysticd
0
Hi ,

It is given that ,

√2 = 1.141 ,

π = 3.141 ,

Now ,

1 ÷ √2 + π

= ( 1/√2 ) + π

= [ √2/( √2 × √2 )] + π

= √2/2 + π

= ( √2 + 2π ) /2

= ( 1.141 + 2 × 3.141 ]/2

= (1.141 + 6.282 )/2

= 7.423/2

= 3.7115

I hope this helps you.

: )
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