Find the 100th number of the series 2, 4, 8, 14, 22, 32....
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we have,
first term=2=a
common diference= 2=d
last term=100=n
since,. 100th term = 2+(100-1)2
=200
first term=2=a
common diference= 2=d
last term=100=n
since,. 100th term = 2+(100-1)2
=200
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