Question

find the 10th term of ap in 3,7,11...​

Answer 1

Answer:

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Step-by-step explanation:

a = 3

d = 4

$a_{10} = a + 9d \\\\ a_{10}= 3 + 9(4) \\\\a_{10} = 3 + 36 \\\\ a_{10} = 39$

Answer 2

Answer:

Given series are <br> 3+7+11+15+19+23+27+31+ . . . . . . <br> and, 1+6+11+16+21+26+31+ . . . . . . As illustration 8. <br> The common differences of the two series are 4 and 5 respectively. Therefore, the series of common terms will form an A.P. with common difference 20 and first term 11. <br> Hence, 10th common term

=11+(10-1)×20=191