Question

Find the 12 th term of ap root2, 3root2, 5root2.....

Answer 1

Given first term = √2 .
Common difference = 3√2 - √2 = 2√2 .

The 12 term of the A. P = √2 + 11(2√2) =√2+22√2 = 23√2 .

Answer 2

Given AP,
√2 , 3√2 , 5√2 , .....
a = $a_{1}$ = √2
$a_{2}$= 3√2
$a_{3}$= 5√2
d = $a_{2}$ - $a_{1}$
= 3√2 - √2 = 2√2
$a_{12}$ = a + 11d
= √2 + 11(2√2)
= √2 + 22√2
= 23√2
12th term of AP is 23√2.