Question

find the 12th term of the A.P .√2,3√2,5√2...

Answer 1

so here
$a \: = \sqrt{2 }$
$d = 2 \sqrt{2}$
12th term is
$\sqrt{2 } + 11 \times 2 \sqrt{2}$
$\sqrt{2 } + 22 \sqrt{2}$

$23 \sqrt{2}$

Answer 2

this is the full solution

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