Find the 25th term of an arithmetic progression 2, 6, 10, 14,
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Answered by
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un = u1+ (n-1)d
u25 = u1+24d
u1 =6
d = 10-6 =4
u25 = 6+24×4 =6+96 =102
Answered by
0
Step-by-step explanation:
un=ul+(n_1)d
u25=ul+24d
au1=6
d=
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