Question

Find the 29th term of progression 4,7,10,13

Answer 1

Answer:

29th term of given series is 88

Step-by-step explanation:

The given Series is Arithmetic  Progression (AP) series

Here,

First Term, 'a' = 4

Second Term = 7

Difference 'd'= 7-4= 3

Now, nth term of AP is,

Tn= a+(n-1)d

29th term (T29)= 4+ (29-1)3

= 4+28x3

= 88

Hence, 29th term of given series is 88