Question

find the 3 term of an AP if their sum is 12 and their product is 28




solve it​

Answer 1

Given:-

Sum of three numbers in AP is 12

Let take numbers as a-d, a, a+d

So, a-d+a+a+d = 12

Product of numbers is 28

Find:-

The numbers?

Solution:-

Sum of numbers is 12

→a−d+a+a+d=12

→3a=12

→a= 3/12 =4

So, The value of a is 4

Product of numbers is 28

→a−d(a)(a+d)=28

→4−d×4×4+d=28

→(4−d)(4+d)= 4/28

→4² −d²=7

→ 16−d² =7

→ −d² =7−16

→ −d² =−9

→ d= 9/3

→ d=3

So, The value of d is 3

First number = a - d = 4-3 = 1

Second number = a = 4

Third number = a + d = 4+3 = 7

Therefore, the numbers are 1 ,4 ,7