Question

find the 31st term of an AP whose 11th term is 12 and 16th term is 73.

Plzzz give answer fast..... ​

Answer 1

Answer is with the explanation.

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Answer 2

Step-by-step explanation:

$t11 = a + 10d = 12.....(1) \\ t16 = a + 15d = 73.....(2) \\ \\ after \: solving \: these \: equations \\ we \: will \: get = > \\ \\ 5d = 61 \\ d = \frac{61}{5} \\ substitute \: d = \frac{61}{5} \: in \: (1) \\ \\ a + 10 \times \frac{61}{5} = 12 \\ a = - 110 \\ \\ t31 = a + 30d \\ \: \: \: \: \: \: \: \: = - 110 + 30 \times \frac{61}{5} \\ \: \: \: \: \: \: \: \: = - 110 + 366 \\ \: \: \: \: \: \: \: \:= \: \: \: \: 256 \\ \\ so \: thirtyfirst \: term \: of \: following \: ap \: is \: 256 \\ \\ \\ hope \: it \: helps \: uh..........$