Question

Find the 41st term of an ap whose 13th term is 79 and 26th term is 157

Answer 1

t13= 79
$a + 12d = 79...1$
t26 = 157
$a + 25d = 157...2$
multiply 2 with -1
$- a - 25d = - 157..3$
adding 1 and 3
$- 13d = - 78 \\ d = 6$
put d=6 in 1
$a + 12 \times 6 = 79 \\ a = 79 - 72 \\ a = 7$
t41 = a+ 40d
7 + 40 × 6
7+240
247
hope this helps you.
don't forget to do it brainleist.

Answer 2

Answer:

if you want to know , how value of a , d so i do step by step division

Step-by-step explanation:

Answer : T41 = 247