Find the 5th term of the sequence
3, 6, 12 etc
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Answer:
3,6,9,12,15,... are in A.P
First term=a=3
Common differenced=6−3=3
n
th
term=t
n
=a+(n−1)d
t
n
=3+(n−1)3=3+3n−3=3n
∴n
th
term is 3n
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