Question

Find the 7th term in the sequence whose nth term is an=n^2/2^n

Answer 1

Answer:

any term you want is the value of n in the sequence or series

Answer 2

49/128

Given:

an = n^2/2^n

To Find:

7 th term of the sequence

Calculating:

an = n^2/2^n

Putting the value of n as 7 we get:

a7 = 7^2/2^7

a7 = 7 x 7/2 x 2 x 2 x 2 x 2 x 2 x 2

(When we raise a number to a power this means that you multiply the number by itself the number of times the power of the number is raised to)

a7 = 49 / 8 x 8 x 2

a7 = 49 / 64 x 2

a7 = 49 / 128

Therefore, the value of the 7th term in the sequence is 49/128.