Question

find the 97th term of the a.p. root 5, 2 root 5, 3 root 5 ,

Answer 1

Given,
a1= √5
a2= 2√5
a3= 3√5
To find,
a97
ATQ,
So,
d= a2 - a1= 2√5-√5= √5
Now,
So,
a97= a + 96d
= √5 + 96√5
= 97√5

Hope this helps you!

Answer 2

USE THE FORMULA

nth term = first term =(no. of terms -1 )difference

so first term is root5

no. of terms is 97

difference is root 5 and put this in formula