Question

Find the A.P. whose 6th term = 5 and 10th term = 9.

Answer 1

given that 6th term=5 and 10th term=9

according to the question

a+5d = 5          (i)

and a+9d = 9   (ii)

by elimination method

substracting equa. (i) from equa. (ii)

a+9d = 9 - a- 5d = 9 - 5

a - a +9d - 5d = 4

4d = 4

d = 4/4

d = 1

putting the value of d in equation (i)

a+5d = 5

a+5(1) = 5

a+5 = 5

a = 5-5

a=0

∴ A.P. = a,(a+d),(a+2d).,.,.,a+(n-1)d

         =0,1,2,3,4,.,.,.,a+(n-1)d

Answer 2

Answer:

given a+5d and a+9d=9

on solving we get:a=0 and d=1

the required AP =a,a+d,a+2d,a+3d,so on

0,1,2,3,4,5,so on ----

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