Find the A.P whose third term is 5 and seventh term is 9.
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Answer:
Step-by-step explanation:
Let the first term be a and common difference be d.
∴Third term = a + 2d = 5........(i)
Seventh term = a + 6d = 9........(ii)
(ii) - (i)⇒ a+ 6d - a - 2d = 9 - 5
⇒4d = 4
⇒d = 1
∴Putting d = 1 in (i) ⇒ a + (2×1) = 5
⇒a + 2 = 5
⇒a = 3
∴The A.P. = a , a + d , a + 2d ,.............so on
⇒3 , (3+1) , (3 + 1 + 1)..........so on
⇒3 , 4 , 5,........so on
Hence , the A.P. = 3 , 4, 5 ,......
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