Find the all four angles of a cyclic quadrilatural A is y° B is 2x° C is 2y° and D is 3x° find ABCD
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hey buddy here is your answer
===> in a cyclic quadrilateral we knows that
==> angle A+ angle C = Angle B + angle D = 180°
==>so now according to statement
==> y°+ 2y°=180 ° --(1)
==>3y°= 180 ° = y= 180/3 = 60°
==> now second angle b+ angle d
==> 2x°+3x°=180°
==> 5x°= 180° = x= 180/5= 36°
now calculate A,B,C and D
A=60°
B= 72°
C= 120°
D = 108°
Hope it helps mark brainliest if satisfied with answer
===> in a cyclic quadrilateral we knows that
==> angle A+ angle C = Angle B + angle D = 180°
==>so now according to statement
==> y°+ 2y°=180 ° --(1)
==>3y°= 180 ° = y= 180/3 = 60°
==> now second angle b+ angle d
==> 2x°+3x°=180°
==> 5x°= 180° = x= 180/5= 36°
now calculate A,B,C and D
A=60°
B= 72°
C= 120°
D = 108°
Hope it helps mark brainliest if satisfied with answer
Vishnuananth:
Nice
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