Math, asked by akash1103, 11 months ago

find the altitude of a rhombus whose area is 22.4 cm ^2 and whose perimeter is 16cm​

Answers

Answered by bswagatam04
19

Hi Mate....

We know that the sides of a Rhombus are always the same.

So, each side of the Rhombus=16/4=4cm.

Now, area of a Rhombus=Base x Height

                                          =Side x Altitude

22.4=Side x Altitude

22.4=4 x Altitude

Altitude=22.4/4

Altitude=5.6 cm

HOPE THIS HELPS.......

Answered by gadakhsanket
12

Dear Student,

● Answer -

h = 5.6 cm

◆ Explanation -

# Given -

A = 22.4 cm^2

P = 16 cm

# Solution -

Length of side of the rhombus is calculated by -

s = P / 4

s = 16 / 4

s = 4 cm

Altitude of a rhombus is -

A = s × h

22.4 = 4 × h

h = 22.4 / 4

h = 5.6 cm

Hence, altitude of the rhombus is 5.6 cm.

Thanks dear. Hope this helps you...

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