find the altitude of a triangle ifs it's area is 520 cm and the base is 16 cm.
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given area of trangle :- 520^2
base of the trangle = 16 cm
area of trangle = 1/2 * b *h
520 = 1/2 * 16 * h
520 = 8 * h
520/8 = h
h = 520/8
h = 65
altitude of the trangle = 65 cm
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Answered by
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Answer:
Altitude of the triangle = 65 cm
Step-by-step explanation:
We have,
Area of the triangle = 520 cm²
Base = 16 cm
We know that,
Area of triangle = (1/2) × base × altitude
Substituting the value
520 cm² = (1/2) × 16 × altitude
520 cm² = 8 × altitude
Altitude = 520/8
Altitude = 65 cm
Hence,
Altitude of the triangle = 65 cm
Hope it helped you and believing you understood it...All the best
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