Question

find the altitude of a triangle whose base and area are 16.4 cm and 246 cm square​

Answer 1

Answer:

$area \: of \: triagle \: = \: \frac{1}{2} \times b \times altitude \: = 246 \: {cm}^{2} \\ \frac{1}{2} \times 16.4 \times altitude \: = \: 246 {cm}^{2} \\ 8.2 \times altitude \: = \: 246 {cm}^{2} \\ altitude \: = \: \frac{246}{8.2} \frac{sq.cm}{cm} \\ altitude \: = \: 30cm$