find the amount and compound interest on₹ 18000 for 2 years 4 months at 12% per annum compounded annually
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Answer:
A=P(1+R100)tP = 10800, R =1212%
and t = 3 years
So, A=10800(1+25200)3=10800(1+18)3=10800(98)3=1080×98×98×98=15377.34
So, Interest =A–P=15377.54−10800=4577.34
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