Question

FIND the amount and compound interest on rupees 4500 for 1 and a half years at 10 percent per annum compounded half-yearly.

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Answer 1

$\huge\underline{\overline{\mid{\bold{\red{\mathcal{QUESTION}}\mid}}}}$

FIND the amount and compound interest on rupees 4500 for 1 and a half years at 10 percent per annum compounded half-yearly.

$\huge\underline{\overline{\mid{\bold{\red{\mathcal{ANSWER}}\mid}}}}$ :

Principal = Rs. 4500

Time = 1.5 years

Rate = 10% per annum

Compounded half yearly

number of half years = 3

Amount when interest is compounded half yearly = ${\bold{P(1+ \frac{R}{200})^{2n}}}$

On putting the values :

$4500(1+ \frac{10}{100})^3 \\ => 5989.5$

Hence, the Amount is Rs. 5989.5

Compound Interest = Amount - Principal

= Rs. 5989.5 - Rs. 4500

= Rs. 1489.5

Hence, the compound interest is Rs. 1489.5

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Answer 2

Answer:

Answer ⤵

Principal = Rs. 4500

Time = 1.5 years

Rate = 10% per annum

Compounded half yearly

number of half years = 3

Amount when interest is compounded half yearly = [tex]{\bold{P(1+ \frac{R}{200})^{2n}}}[\tex]

On putting the values :

[tex]\begin{gathered} 4500(1+ \frac{10}{100})^3 \\ = > 5989.5 \end{gathered}[\tex]

Hence, the Amount is Rs. 5989.5

Compound Interest = Amount - Principal

= Rs. 5989.5 - Rs. 4500

= Rs. 1489.5 ans.

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