Question

find the amount to be paid at the end of 3 years in the following cases. Principal =rs 1200 at 12%p.a.​

Answer 1

$\sf\underline{Step-by-step \: explanation}$

● Amount = SI + Principal

● Amount = x + Rs. 1200

● To find x which means Simple interest, we use,

●
$si \: = \: \frac{p \: \times \: r \: \times t}{100}$

● P = Rs. 1200

● R = 12% p.a.

● T = 3 years.

Accordingly,

$x \: = \: \frac{1200 \: \times 12 \: \times \: 3}{100}$

$\tt{After \: Cancellation...}$

Rs. 432

Now,

Amount = SI + P

A = x + Rs. 1200

A = Rs. 432 + Rs. 1200

A = Rs. 1632

● Hence, the required amount is,

${\mathcal{\boxed{\boxed{Rs. \: 1632}}}}$

Answer 2

Refer the attachment above for step by step Solution ⚡

Another type of question ✓

Find the amount to be paid at the end of 3 years in each case- principal= Rs7,500 at 5% p.a.

Answer:-

₹ 8625

Step-by-step explanation:-

P = ₹7500

R = 5%

T = 3 years

$\sf{ S.I. = \dfrac{ = P \times R \times T}{100}}$

$\sf{S.I. = \dfrac{7500 \times 5 \times 3}{100} }$

$\sf{S.I. = \dfrac{75 \cancel{00} \times 5 \times 3}{ \cancel{100}}}$

$\sf{S.I. = 75 \times 5 \times 3}$

S.I. = ₹1125

Now, for finding Amount,

A = P + I

A = 7500 + 1125

A = ₹8625

Therefore, Amount paid at the end of 3rd year = ₹8625

Here,

P = Principal

R = Rate

T = Time

S.I. = Simple interest

A = Amount

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