Question

find the angle between two vectors a=i+j-2k and b=i+j-k​

Answer 1

⭐Solution ⭐

✏given here

a= i+j-2k

b= i+i-k

➡Angle between two vectors

♠ cos x = (a.b)/(|a|. |b|)

= (i+j-2k)(i+j-k)/[(√{1²+1²+(-2)²}{1²+1²+(-1)²}

= (1+1+2)/(√6)(√3)

= 4/3√2

= 2√2/3

So,

X = Cos^(-1)(2√2/3)

✏Hopes its helps u.