find the angle between two vectors a=i+j-2k and b=i+j-k
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⭐Solution ⭐
✏given here
a= i+j-2k
b= i+i-k
➡Angle between two vectors
♠ cos x = (a.b)/(|a|. |b|)
= (i+j-2k)(i+j-k)/[(√{1²+1²+(-2)²}{1²+1²+(-1)²}
= (1+1+2)/(√6)(√3)
= 4/3√2
= 2√2/3
So,
X = Cos^(-1)(2√2/3)
✏Hopes its helps u.
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