Question

what is the answer of above question?​

Answer 1

Answer:

2.<1% of 22.4 L

Explanation:

At STP, volume occupied by one mole of gas is 22.4 L.

However, 1 mole H2O = 18 gm

Now, assuming density of water equal to 1,

18 gm H2O=18 ml H20

% of actual volume occupied= Actual volume x 100/ Volume of water vapour at STP

= 18x100/22400 (22.4 L= 22400 ml)

= 0.08%

so < 1% of 22.4 L is the Answer