Question

find the angle between y=3x+2 and y=-1/3 x​

Answer 1

Answer:  ANGLE = $\frac{\pi }{2}$

Step-by-step explanation:

line : $L_{1}$ => y = 3x + 2

line : $L_{2}$ => y = $-\frac{1}{3} x$

Let angle between $L_{1}$ and $L_{2}$ be " $\alpha$ "

we know that  $tan\alpha = \frac{m-n}{1+m.n }$

m and n are slopes of $L_{1}$ and $L_{2}$ respectively.

m = 3 and n = -1/3

$tan\alpha = \frac{3+\frac{1}{3} }{1-3*\frac{1}{3} } \\\\tan \alpha = \frac{10}{0} \\\\\alpha = tan ^{-1} ( + infinity )\\\\\alpha = \frac{\pi }{2}$