find the angle, if its supplement is 3 times of its complement :
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Answered by
7
let one angle be x
now
supplement of angle x is (180-x)
complement of angle x is (90-x)
according to the question..
(180-x)=3(90-x)
180-x=270-3x
2x=90
x=45
therefore the angle is 45
hope this helps:p
now
supplement of angle x is (180-x)
complement of angle x is (90-x)
according to the question..
(180-x)=3(90-x)
180-x=270-3x
2x=90
x=45
therefore the angle is 45
hope this helps:p
Anonymous:
do mark as brainliest:p
Answered by
3
hi friend
let the angle be x
its compliment be (90-x)
and its supplement be(180-x)
ATQ 180-x=3(90-x)
180-x=270-3x
3x-2x=270-180
2x= 90
x= 45
so the required angle = 45°
___________________________________________________________
let the angle be x
its compliment be (90-x)
and its supplement be(180-x)
ATQ 180-x=3(90-x)
180-x=270-3x
3x-2x=270-180
2x= 90
x= 45
so the required angle = 45°
___________________________________________________________
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