Solve the linear equation using elimination method
3x+2y=8
2x-3y=1
Answers
Answered by
2
Let us eliminate x.
2(3x+2y=8)------(eq.1)
3(2x-3y=1)
6x+4y=16
(-)
6x-9y=3
-------------
13y=1
-------------
y=13/13
y=1.
x=(8-2y)/3. (From eq.1)
x=6/3
x=2.
Hope it helps you.
2(3x+2y=8)------(eq.1)
3(2x-3y=1)
6x+4y=16
(-)
6x-9y=3
-------------
13y=1
-------------
y=13/13
y=1.
x=(8-2y)/3. (From eq.1)
x=6/3
x=2.
Hope it helps you.
Answered by
1
3x+2y=8............I
2x-3y=1.............II
by multiplying equation I by 2 and II by 3 we get,
6x+4y=16.........III
&6x-9y=3.........IV
by subtracting equation IV from III we get,
6x+4y=16
-(6x-9y=3)
⇒6x+4y=16
-6x+9y=-3
⇒13y=13
∴y=13/13=1
by substituting the value of y in the equation II we get,
2x-3×1=1
∴2x-3=1
∴2x=3+1
∴2x=4
∴x=-2
2x-3y=1.............II
by multiplying equation I by 2 and II by 3 we get,
6x+4y=16.........III
&6x-9y=3.........IV
by subtracting equation IV from III we get,
6x+4y=16
-(6x-9y=3)
⇒6x+4y=16
-6x+9y=-3
⇒13y=13
∴y=13/13=1
by substituting the value of y in the equation II we get,
2x-3×1=1
∴2x-3=1
∴2x=3+1
∴2x=4
∴x=-2
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