Question

find the angle of the triangle whose angles are (2A) =(3B) =(6C)

Answer 1

2A = 3B = 6C = K( let )

A = K/2
B=K/3
C=K/6

we know,
sum of all angles of traingle is equal to 180°
so,
A + B + C= 180°
K/2 + K/3 +K/6 = 180°
K = 180°

so, A = K/2 = 180°/2 =90°
B = K/3 = 180°/3 = 60°
C = K/6 = 180°/6 = 30°

Answer 2

TAKE 2A=6C
A=3C -(1)
take 3B=6C
B=2C
therec angle A,B,C
A+B+C=180-(3) in a triangle the sum of the three angle of trangle is 180 degree
substating (1) and (2) in(3)
3C+2C+C=180
6C=180
C=30 subsitute the value C in (1) and (2)
A=3C
A=3*30=90
B=2C
B=2*30=60
the angle= A=90,B=60,C=30