Find the angle which is 10 more than thrice its complement
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Let the complement angle be x
then the angle be 3x + 10
A/q
x + 3x+ 10 = 90
=> 4x + 10 = 90
=> 4x = 80
=>. x = 80/4 = 20°
Hence,
the req angle = 3x + 10
=3×20 + 10
= 70° Ans...
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