Find the angle which is double to its supplement.
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6
let the angle be X . then , double of its supplement = ( 180-2x )°
X =( 180-2x)°
3x = 180°
X = 180/3
X = 60°
hence the required angle is 60°
X =( 180-2x)°
3x = 180°
X = 180/3
X = 60°
hence the required angle is 60°
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let the angle be = x
doble of its angle = 2x
supplement angle = 180°
x = 180 - 2x
3x = 180°
x = 180/3
x = 60°
the value of x is 60°
doble of its angle = 2x
supplement angle = 180°
x = 180 - 2x
3x = 180°
x = 180/3
x = 60°
the value of x is 60°
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