Find the angle whose supplement is six times its complement?
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6x
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Let the angle be x
Complement angle : A pair of angles whose sum is 90°
So, complement of x = 90-x
Supplement angle = A pair of angles whose sum is 180°
So, Supplement of x = 180-x
Now we are given that supplement of x is six times its complement
So,
ATQ,
180-x=6(90-x)
180-x=540-6x
6x-x=540-180
5x=360
x=72
Thus the angle whose supplement is six times its complement is 72°
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